30x^2-28x=18

Solution for 30x^2-28x=18 equation:

30x^2-28x=18

We move all terms to the left:

30x^2-28x-(18)=0

a = 30; b = -28; c = -18;
Δ = b2-4ac
Δ = -282-4·30·(-18)
Δ = 2944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2944}=\sqrt{64*46}=\sqrt{64}*\sqrt{46}=8\sqrt{46}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-8\sqrt{46}}{2*30}=\frac{28-8\sqrt{46}}{60}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+8\sqrt{46}}{2*30}=\frac{28+8\sqrt{46}}{60}
$